Messages

Hello Liviu,
I used your trick and it works! Then, I made combinations of 6 by 3, for a total of 20, using the constraint "all teachers interval max days per week", max occupied = 5. I also made another test for combinations of 6 by 2 (15 combinations) to limit to max 1 day each teacher works from 1st hour to last hour (max occupied = 3). Even if this is a very strong constraint, it also works! Very good job! Great! Thank you again for your precious trick. 

Hallo Liviu,
thank you for your fast reply. I will try the 3rd trick in the next days and I will let you know.
See you soon 

Hi guys,
I am sure that this problem has a solution, but I cannot find anything similar in the forum.
I made timetable for my Italian school. My constraints are very simple; for all teachers: max 5 hours daily, max 5 days per week, min 2 hours daily, min 5 days per week, max 1 gap daily, max 3 gaps per week. Every day is 6 hours long for students: from 8:00 to 14:00.

The software is great and everything is ok but now I need one more constraint for teachers: every teacher must work 6 hours (including 1 gap) for max 2 days per week. In fact, considering my constraints, it can happen that a teacher works a total of 6 hours (from 8:00 to 14:00) for 3 days (including 3 gaps) and I want to avoid this for educational reasons.
This means, in other words, that a teacher can start at 8:00 and end at 14:00 for no more than 2 times a week.

Is it possible to do that? And how? I hope to explain my problem clearly.

Thank you very much.